1864 United States presidential election in Delaware

The 1864 United States presidential election in Delaware took place on November 8, 1864, as part of the 1864 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1864 United States presidential election in Delaware

November 8, 1864
 
Nominee George B. McClellan Abraham Lincoln
Party Democratic National Union
Home state New Jersey Illinois
Running mate George H. Pendleton Andrew Johnson
Electoral vote 3 0
Popular vote 8,767 8,155
Percentage 51.81% 48.19%

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
Republican

Delaware was won by the 4th Commanding General of the United States Army George B. McClellan (DPennsylvania), running with Representative George H. Pendleton, with 51.81% of the popular vote against the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 48.19% of the popular vote.[1]

Results

1864 United States presidential election in Delaware[1]
Party Candidate Votes %
Democratic George B. McClellan 8,767 51.81%
National Union Abraham Lincoln 8,155 48.19%
Total votes 16,922 100.00%

See also

References

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