1940 United States presidential election in Delaware

The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

1940 United States presidential election in Delaware

November 5, 1940[1]

All 3 Delaware votes to the Electoral College
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York Indiana
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 3 0
Popular vote 74,599 61,440
Percentage 54.7% 45.1%

County Results
Roosevelt
  50-60%


President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

Delaware was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (RIndiana), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote.[3][4]

Results

1940 United States presidential election in Delaware
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 74,599 54.70%
Republican Wendell Willkie 61,440 45.05%
Write-in 335 0.25%
Total votes 136,334 100%
County Dem Rep Oth
Kent 9,226 8,079 48
New Castle 52,167 41,508 261
Sussex 13,206 11,853 26
STATEWIDE 74,599 61,440 335

See also

References


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.