1928 United States presidential election in Delaware

The 1928 United States presidential election in Delaware took place on November 6, 1928. All contemporary 48 states were part of the 1928 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

1928 United States presidential election in Delaware

November 6, 1928

Nominee Herbert Hoover Al Smith Party Republican Democratic Home state California New York Running mate Charles Curtis Joseph T. Robinson Electoral vote 3 0 Popular vote 68,860 36,643 Percentage 65.03% 34.60%

County Results Hoover   50-60%   60-70%

President before election Calvin Coolidge Republican Elected President Herbert Hoover Republican

Elections in Delaware
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Delaware was won by Republican Secretary of Commerce Herbert Hoover of California, who was running against Democratic Governor of New York Alfred E. Smith. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith's running mate was Senator Joseph Taylor Robinson of Arkansas.

Hoover won with a majority of 65.03% of the vote to Smith's 34.60%, a margin of 30.43%. Socialist candidate Norman Thomas finished a distant third, with 0.31%. Hoover’s performance is easily the best by any presidential candidate in Delaware, surpassing its nearest rival from Barack Obama in 2008 by 3.12%.[1]