1892 United States presidential election in Delaware

The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

1892 United States presidential election in Delaware

November 8, 1892
 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Adlai Stevenson I Whitelaw Reid
Electoral vote 3 0
Popular vote 18,581 18,077
Percentage 49.90% 48.55%

County Results
Cleveland
  40-50%
  50-60%


President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Results

1892 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 18,581 49.90% 3
Republican Benjamin Harrison (incumbent) 18,077 48.55% 0
Prohibition John Bidwell 564 1.51% 0
Write-ins Scattered 13 0.03% 0
Totals 37,235 100.00% 3
Voter turnout

See also

References

  1. Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware

Notes

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