1880 United States presidential election in Delaware

The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1880 United States presidential election in Delaware

November 2, 1880

Nominee Winfield Scott Hancock James A. Garfield Party Democratic Republican Home state Pennsylvania Ohio Running mate William Hayden English Chester A. Arthur Electoral vote 3 0 Popular vote 15,181 14,148 Percentage 51.53% 48.03%

County Results Hancock   50-60% Garfield   50-60%

President before election Rutherford B. Hayes Republican Elected President James Garfield Republican

Elections in Delaware
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State government General elections 2010 2012 2014 2016 2018 Gubernatorial elections 1795 1798 1801 1804 1807 1810 1813 1944 1948 1952 1956 1960 1964 1968 1972 1976 1980 1984 1988 1992 1996 2000 2004 2008 2012 2016 2020 Lieutenant gubernatorial elections 2004 2008 2012 2016 2020 Senate elections 2018 2020 House of Representatives elections 2008 2010 2012 2014 2016 2018 2020 Special elections 10th Senate district, 2017
Wilmington Mayoral elections 2012 2016 2020

Delaware was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]