1948 United States presidential election in Delaware

The 1948 United States presidential election in Delaware took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

1948 United States presidential election in Delaware

November 2, 1948[1]

All 3 Delaware votes to the Electoral College
 
Nominee Thomas E. Dewey Harry S. Truman
Party Republican Democratic
Home state New York Missouri
Running mate Earl Warren Alben W. Barkley
Electoral vote 3 0
Popular vote 69,588 67,813
Percentage 50.0% 48.8%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

Delaware was won by Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 50.04% of the popular vote, against incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 48.76% of the popular vote.[3][4] This is the last time that New Castle county did not back the statewide winner, when the Democratic candidate would win a presidential election without Delaware, and the last election until 2000 when Delaware failed to support the overall winner of the presidency, and electoral college.

Results

1948 United States presidential election in Delaware
Party Candidate Votes %
Republican Thomas Dewey 69,588 50.04%
Democratic Harry S. Truman (inc.) 67,813 48.76%
Progressive Henry A. Wallace 1,050 0.75%
Write-in 622 0.45%
Total votes 139,073 100.00%

See also

References


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