1868 United States presidential election in Oregon
The 1868 United States presidential election in Oregon took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Oregon |
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Oregon voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a narrow margin of 0.74%.
As a result of his win, Seymour became the first Democratic presidential candidate to ever win Oregon. Another Democrat would not win Oregon again on a presidential level until Woodrow Wilson won the state in 1912.
Results
1868 United States presidential election in Oregon[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Horatio Seymour of New York | Francis Preston Blair, Jr. of Missouri | 11,125 | 50.37% | 3 | 100.00% | ||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 10,961 | 49.63% | 0 | 0.00% | ||
Total | 22,086 | 100.00% | 3 | 100.00% |
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