1940 United States presidential election in Connecticut
The 1940 United States presidential election in Connecticut took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.
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 County Results
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| Elections in Connecticut |
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Connecticut was won by popular incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of Indiana. Roosevelt ran with Henry A. Wallace of Iowa as his running mate, and Willkie ran with Senator Charles L. McNary of Oregon.
Roosevelt won Connecticut by a comfortable margin of 7.14%.
Results
| 1940 United States presidential election in Connecticut[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Delano Roosevelt of New York | Henry Agard Wallace of Iowa | 417,621 | 53.44% | 8 | 100.00% | ||
| Republican | Wendell Willkie of Indiana | Charles Linza McNary of Oregon | 361,819 | 46.30% | 0 | 0.00% | ||
| Communist | Earl Russell Browder of Kansas | James W. Ford of New York | 1,091 | 0.14% | 0 | 0.00% | ||
| Socialist Labor | John W. Aiken of Connecticut | Aaron M. Orange of New York | 971 | 0.12% | 0 | 0.00% | ||
| Total | 781,502 | 100.00% | 8 | 100.00% | ||||
References
- "1940 Presidential General Election Results – Connecticut". U.S. Election Atlas. Retrieved 23 December 2013.
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