1948 United States presidential election in Connecticut
The 1948 United States presidential election in Connecticut took place on November 7, 1944, as part of the 1948 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.
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 County Results
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| Elections in Connecticut |
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Connecticut was won by Republican candidate New York governor Thomas E. Dewey over Democratic candidate, incumbent President Harry S. Truman.
Dewey won the state by a very narrow margin of 1.64%.
Results
| 1948 United States presidential election in Connecticut[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Thomas Edmund Dewey of New York | Earl Warren of California | 437,754 | 49.55% | 8 | 100.00% | ||
| Democratic | Harry S. Truman of Missouri | Alben William Barkley of Kentucky | 423,297 | 47.91% | 0 | 0.00% | ||
| Progressive | Henry Agard Wallace of Iowa | Glen Hearst Taylor of Idaho | 13,713 | 1.55% | 0 | 0.00% | ||
| Socialist | Norman Thomas of New York | Tucker Powell Smith of Michigan | 6,964 | 0.79% | 0 | 0.00% | ||
| Socialist Labor | Edward A. Teichert of Pennsylvania | Stephen Emery of New York | 1,184 | 0.13% | 0 | 0.00% | ||
| Socialist Workers | Farrell Dobbs of Minnesota | Grace Carlson of Minnesota | 606 | 0.07% | 0 | 0.00% | ||
| Total | 883,518 | 100.00% | 8 | 100.00% | ||||
References
- "1948 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 23 December 2013.
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