Dominical letter

A simpler method suitable for finding the year's dominical letter was discovered in 2010. It is called the "odd plus 11" method.[7]

The procedure accumulates a running total T as follows:

1. Let T be the year's last two digits.
2. If T is odd, add 11.
3. Let T = T/2.
4. If T is odd, add 11.
5. Let T = T mod 7.
6. Count forward T letters from the century's dominical letter (A, C, E or G see above) to get the year's dominical letter.

The formula is

${\displaystyle \left({\frac {y+11(y{\bmod {2}})}{2}}+11\left({\frac {y+11(y{\bmod {2}})}{2}}{\bmod {2}}\right)\right){\bmod {7}}.}$

This rule was stated by Augustus de Morgan:

1. Add 1 to the given year.
2. Take the quotient found by dividing the given year by 4 (neglecting the remainder).
3. Take 16 from the centurial figures of the given year if that can be done.
4. Take the quotient of III divided by 4 (neglecting the remainder).
5. From the sum of I, II and IV, subtract III.
6. Find the remainder of V divided by 7: this is the number of the Dominical Letter, supposing A, B, C, D, E, F, G to be equivalent respectively to 6, 5, 4, 3, 2, 1, 0.[6]

So the formulae (using the floor function) for the Gregorian calendar is

${\displaystyle 1.\left(1+{\text{year}}+{\Big \lfloor }{\frac {\text{year}}{4}}{\Big \rfloor }+{\Big \lfloor }{\frac {{\text{year}}-1600}{400}}{\Big \rfloor }-{\Big \lfloor }{\frac {{\text{year}}-1600}{100}}{\Big \rfloor }\right){\bmod {7}}.}$

It is equivalent to

${\displaystyle 2.\left({\text{year}}+{\Big \lfloor }{\frac {\text{year}}{4}}{\Big \rfloor }+{\Big \lfloor }{\frac {\text{year}}{400}}{\Big \rfloor }-{\Big \lfloor }{\frac {\text{year}}{100}}{\Big \rfloor }-1\right){\bmod {7}}}$

and

${\displaystyle 3.\left(y+{\Big \lfloor }{\frac {y}{4}}{\Big \rfloor }+5(c{\bmod {4}})-1\right){\bmod {7}}}$     (where ${\displaystyle {\text{y}}}$ = last two digits of the year, ${\displaystyle {\text{c}}}$ = century part of the year).

For example, to find the Dominical Letter of the year 1913:

1. (1 + 1913 + 478 + 0 − 3) mod 7 = 2

2. (1913 + 478 + 4 − 19 − 1) mod 7 = 2

3. (13 + 3 + 15 -1) mod 7 = 2

Hence, the Dominical Letter is E in the Gregorian calendar.

De Morgan's rules no. 1 and 2 for the Julian calendar:

${\displaystyle 1.}$ and ${\displaystyle 2.\left({\text{year}}+{\Big \lfloor }{\frac {\text{year}}{4}}{\Big \rfloor }-3\right){\bmod {7}}}$

To find the Dominical Letter of the year 1913 in the Julian calendar:

• (1913 + 478 − 3) mod 7 = 1

Hence, the Dominical Letter is F in the Julian calendar.

In leap years the formulae above give the Dominical Letter for the last ten months of the year. To find the Dominical Letter for the first two months of the year to the leap day (inclusive) subtract 1 from the calculated number representing the original Dominical Letter; if the new number is less than 0, it must be changed to 6.

The "doomsday" concept in the doomsday algorithm is mathematically related to the Dominical letter. Because the letter of a date equals the dominical letter of a year (DL) plus the day of the week (DW), and the letter for the doomsday is C except for the portion of leap years before February 29 in which it is D, we have:

${\displaystyle {\begin{aligned}{\text{C}}&=({\text{DL}}+{\text{DW}}){\bmod {7}}\\{\text{DL}}&=({\text{C}}-{\text{DW}}){\bmod {7}}\\{\text{DW}}&=({\text{C}}-{\text{DL}}){\bmod {7}}\end{aligned}}}$

Note: G = 0 = Sunday, A = 1 = Monday, B = 2 = Tuesday, C = 3 = Wednesday, D = 4 = Thursday, E = 5 = Friday, and F = 6 = Saturday, i.e. in our context, C is mathematically identical to 3.

Hence, for instance, the doomsday of the year 2013 is Thursday, so DL = (3 − 4) mod 7 = 6 = F. The dominical letter of the year 1913 is E, so DW = (3 − 5) mod 7 = 5 = Friday.

If the year of interest is not within the table, use a tabular year which gives the same remainder when divided by 400 (Gregorian calendar) or 700 (Julian calendar). Note the different rules for leap years:

• Gregorian calendar: every year which divides exactly by 4, but of century years only those which divide exactly by 400; therefore ignore the left-hand letter given for a century year which is not a leap year.
• Julian calendar: every year which divides exactly by 4.

When a country switched to the Gregorian calendar, there could be some unusual combinations of dominical letters.

• 1582: Many Catholic countries switched to the Gregorian calendar Friday 15 October. The table above indicates that year 1582 had the dominical letter G in the Julian calendar and C in the Gregorian one. So the dominical letters for 1582 in these Catholic countries became GC for mixing the two calendars used in this legal year, a special combination not seen before and after with a single calendar used in the same legal year.
• 1752: The British Empire and its colonies switched to the Gregorian calendar Thursday 14 September. 1752, a leap year, had in the Julian calendar dominical letters ED and in the Gregorian one dominical letters BA, so the dominical letters for 1752 in Britain were EDA, a very special combination which also only applies to this legal year.

Note that this table does not work for AD years at the early stage of the real Julian calendar before year AD 42 or for any BC year, except when using the Julian calendar rules for proleptic dates (which are different from effective historic dates, whose effective calendar in use depend on the location of dated events, sometimes differently between political/civil or religious purposes in places where both calendars can still coexist). The duration of months, and the number and placement of intercalated days in February also changed inconsistently before AD 42 in the early Julian calendars, depending on places and years, causing finally lot of confusion in the population (so dating events precisely in that period is often difficult, unless they are correlated with observed lunar cycles, or with days of the week, or with another calendar).

In these early AD years and in all BC years, with the effective Julian calendars used locally to align the counting of years (but still with the tradition inherited from the earlier Roman calendar for noting days in each year), a variable number of days at end of the months (after the last day of its ides but before the last day of calends which started the next month) were also still counted relatively from the start of the next named month (on the last day of its calends), and years were theoretically starting on 1 March (but with the last days of the year in February also counted from the New Year's Day in March). As well, all these early years were effectively counted inclusively and positively from a different, much earlier epoch in other eras, such as the supposed foundation of Rome, or the accession to power of a local ruler (and still not relatively to the supposed date of birth of Christ, which was fixed later arbitrarily by a Christian reform for the modern Julian calendar so that this epoch for the Christian era starts now on 1 January in proleptic year AD 1 of the modern Julian calendar, but the real date of birth of Christ is still not known precisely but certainly falls before, somewhere in the last few BC years).

Instructions

For Julian dates before 1300 and after 1999 the year in the table which differs by an exact multiple of 700 years should be used. For Gregorian dates after 2299, the year in the table which differs by an exact multiple of 400 years should be used. The values "r0" through "r6" indicate the remainder when the Hundreds value is divided by 7 and 4 respectively, indicating how the series extend in either direction. Both Julian and Gregorian values are shown 1500–1999 for convenience.

The corresponding numbers in the far left hand column on the same line as each component of the date (the hundreds, remaining digits and month) and the day of the month are added together. This total is then divided by 7 and the remainder from this division located in the far left hand column. The day of the week is beside it. Bold figures (e.g., 04) denote leap year. If a year ends in 00 and its hundreds are in bold it is a leap year. Thus 19 indicates that 1900 is not a Gregorian leap year, (but bold 19 in the Julian column indicates that it is a Julian leap year, as are all Julian x00 years). 20 indicates that 2000 is a leap year. Use bold Jan and Feb only in leap years.

For determination of the day of the week (1 January 2000, Saturday)

• the day of the month: 1
• the month: 6
• the year: 0
• the century mod 4 for the Gregorian calendar and mod 7 for the Julian calendar 0
• adding 1 + 6 + 0 + 0 = 7. Dividing by 7 leaves a remainder of 0, so the day of the week is Saturday.

Note that the date (and hence the day of the week) in the Revised Julian and Gregorian calendars is the same up until 28 February 2800, and that for large years it may be possible to subtract 6300 or a multiple thereof before starting so as to reach a year within or closer to the table.

To look up the weekday of any date for any year using the table, subtract 100 from the year, divide the number obtained by 100, multiply the resulting quotient (omitting fractions) by seven and divide the product by nine. Note the quotient (omitting fractions). Enter the table with the Julian year, and just before the final division add 50 and subtract the quotient noted above.

Example: What is the day of the week of 27 January 8315?

8315 has the same calendar as 1915 and 2010. The day of the week is Wednesday.

To find the dominical letter, calculate the day of the week for either 1 January or 1 October. If it is Sunday, the Sunday Letter is A, if Saturday B, and similarly backwards through the week and forwards through the alphabet to Monday, which is G.

Leap years have two letters, so for January and February calculate the day of the week for 1 January and for March to December calculate the day of the week for 1 October.

Leap years are all years that divide exactly by four, with the following exceptions:

Gregorian calendar – all years divisible by 100, except those that divide exactly by 400.

Revised Julian calendar – all years divisible by 100, except those with a remainder of 200 or 600 when divided by 900.