1860 United States presidential election in Wisconsin
The 1860 United States presidential election in Wisconsin was held on November 6, 1860 as part of the 1860 United States presidential election. State voters chose five electors to the Electoral College, who voted for president and vice president.
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| Elections in Wisconsin |
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Wisconsin was won by the Republican Party candidate Abraham Lincoln with 57% of the popular vote, winning the states five electoral votes.
Results
| 1860 United States presidential election in Wisconsin[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 86,113 | 56.59% | 5 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 65,021 | 42.73% | 0 | 0.00% | ||
| Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 888 | 0.58% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 161 | 0.11% | 0 | 0.00% | ||
| Total | 152,183 | 100.00% | 5 | 100.00% | ||||
References
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