1880 United States presidential election in Wisconsin

The 1880 United States presidential election in Wisconsin was held on November 2, 1880 as part of the 1880 United States presidential election. State voters chose ten electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in Wisconsin

November 2, 1880
 
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 10 0
Popular vote 144,398 114,644
Percentage 54.04% 42.91%

County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

Republican Party candidate James A. Garfield won Wisconsin with 54.04 percent of the popular vote, winning the state's ten electoral votes.[1]

Results

Presidential Candidate Running Mate Party Electoral Vote (EV) Popular Vote (PV)
James A. Garfield of Ohio Chester A. Arthur Republican 10 144,398 54.04%
Winfield Scott Hancock William Hayden English Democratic 0 114,644 42.91%
James B. Weaver Barzillai J. Chambers Greenback 0 7,986 2.99%
John W. Phelps Samuel C. Pomeroy American (Know Nothing) 0 91 0.03%
Neal Dow Henry Adams Thompson Prohibition 0 68 0.03%

References

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