1879 Rhode Island gubernatorial election
The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.
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| Elections in Rhode Island |
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General election
Candidates
Major party candidates
- Charles C. Van Zandt, Republican
- Thomas W. Segar, Democratic
Other candidates
- Samuel Hill, Independent
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Charles C. Van Zandt | 9,717 | 62.09% | ||
| Democratic | Thomas W. Segar | 5,506 | 35.18% | ||
| Greenback | Samuel Hill | 318 | 2.03% | ||
| Majority | 4,211 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
- Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.
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