1936 United States presidential election in Rhode Island

The 1936 United States presidential election in Rhode Island was held on November 3, 1936. The state voters chose four electors to the Electoral College, who voted for president and vice president.

1936 United States presidential election in Rhode Island

November 3, 1936

Nominee Franklin D. Roosevelt Alf Landon William Lemke Party Democratic Republican Union Home state New York Kansas North Dakota Running mate John Nance Garner Frank Knox Thomas C. O'Brien Electoral vote 4 0 0 Popular vote 165,238 125,031 19,569 Percentage 53.10% 40.18% 6.29%

County Results Roosevelt   40-50%   50-60% Landon   40-50%   50-60%

President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Elections in Rhode Island
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Rhode Island voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who won the state by a margin of 12.92%.