1886 Rhode Island gubernatorial election
The 1886 Rhode Island gubernatorial election was held on April 7, 1886. Incumbent Republican George P. Wetmore defeated Democratic nominee Amasa Sprague with 53.26% of the vote.
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| Elections in Rhode Island |
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General election
Candidates
Major party candidates
- George P. Wetmore, Republican
- Amasa Sprague, Democratic
Other candidates
- George H. Slade, Prohibition
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | George P. Wetmore | 14,340 | 53.26% | ||
| Democratic | Amasa Sprague | 9,994 | 37.12% | ||
| Prohibition | George H. Slade | 2,585 | 9.60% | ||
| Majority | 4,346 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
- Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 14, 2020.
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