1996 United States presidential election in Rhode Island

The 1996 United States presidential election in Rhode Island took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

1996 United States presidential election in Rhode Island

November 5, 1996
Turnout64.8%[1] 11.8 pp
 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Patrick Choate
Electoral vote 4 0 0
Popular vote 233,050 104,683 43,723
Percentage 59.71% 26.82% 11.20%

County Results
Clinton
  50-60%
  60-70%


President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

Rhode Island was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 59.71% to 26.82% by a margin of 32.89%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 11.20% of the popular vote.[2]

Results

1996 United States presidential election in Rhode Island
Party Candidate Running mate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) Al Gore 233,050 59.71% 4
Republican Bob Dole Jack Kemp 104,683 26.82% 0
Reform Ross Perot Patrick Choate 43,723 11.20% 0
Green Ralph Nader Winona LaDuke 6,040 1.55% 0
Libertarian Harry Browne Jo Jorgensen 1,109 0.28% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 1,021 0.26% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 435 0.11% 0
Workers World Party Monica Moorehead Gloria La Riva 186 0.05% 0
No party Write-in 37 0.01% 0

By county

William Jeferson Clinton

Democratic

Robert Joseph Dole

Republican

Henry Ross Perot

Reform

Various candidates

Others parties

County # % # % # % # %
Providence 134,866 63.6% 49,901 23.5% 22,724 10.7% 4,631 2.2%
Kent 41,018 57.3% 19,992 28.0% 9,240 12.9% 1,276 1.8%
Bristol 12,257 56.6% 6,988 32.2% 1,990 9.2% 436 2.0%
Newport 18,951 54.0% 11,500 32.8% 3,785 10.8% 860 2.5%
Washington 25,598 52.1% 16,302 32.7% 5,984 12% 1,588 3.2%

See also

References

  1. This figure is calculated by dividing the total number of votes cast in 1996 (390,247) by an estimate of the number of registered voters in Rhode Island in 1996 (602,692). See "Voter Turnout, 1996". Rhode Island Board of Elections. Retrieved February 6, 2018.
  2. http://uselectionatlas.org/RESULTS/index.html
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