1930 Rhode Island gubernatorial election

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

1930 Rhode Island gubernatorial election

November 4, 1930
 
Nominee Norman S. Case Theodore F. Green
Party Republican Democratic
Popular vote 112,070 108,558
Percentage 50.53% 48.95%

Governor before election

Norman S. Case
Republican

Elected Governor

Norman S. Case
Republican

General election

Candidates

Major party candidates

  • Norman S. Case, Republican
  • Theodore F. Green, Democratic

Other candidates

  • Charles H. Dana, Socialist

Results

1930 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Norman S. Case 112,070 50.53%
Democratic Theodore F. Green 108,558 48.95%
Socialist Charles H. Dana 1,168 0.53%
Majority 3,512
Turnout
Republican hold Swing

References

  1. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 7, 2020.
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