1890 Rhode Island gubernatorial election

The 1890 Rhode Island gubernatorial election was held on April 2, 1890. Democratic nominee John W. Davis defeated incumbent Republican Herbert W. Ladd with 48.76% of the vote.

1890 Rhode Island gubernatorial election
April 2, 1890
 
Nominee John W. Davis Herbert W. Ladd
Party Democratic Republican
Popular vote 20,548 18,988
Percentage 48.76% 45.06%
Governor before election

Herbert W. Ladd
Republican

 Elected Governor

John W. Davis
Democratic

Elections in Rhode Island
Federal government
U.S. President
U.S. Senate
U.S. House
State government
General elections
Gubernatorial elections
State Senate elections
State House of Representatives elections
Providence
Mayoral elections

General election

Candidates

Major party candidates

  • John W. Davis, Democratic
  • Herbert W. Ladd, Republican

Other candidates

  • John H. Larry, Prohibition
  • Arnold B. Chace, Union[1][2][3]

Results
1890 Rhode Island gubernatorial election[4]
Party Candidate Votes % ±%
Democratic John W. Davis 20,548 48.76%
Republican Herbert W. Ladd 18,988 45.06%
Prohibition John H. Larry 1,820 4.32%
Independent Arnold B. Chace 752 1.78%
Majority 1,560
Turnout
Democratic gain from Republican Swing

References
  1. "A Quaker for Governor". The sun. New York, N.Y. March 2, 1890. p. 18. Retrieved 9 January 2021.
  2. "For the Suppression of Rum". Pittsburg dispatch. Pittsburg, Pa. February 26, 1890. p. 4. Retrieved 9 January 2021.
  3. "Personal and Political". The herald. Milbank, S.D. March 4, 1890. p. 2. Retrieved 9 January 2021.
  4. Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 27, 2020.
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