Seward Township, Winnebago County, Illinois

Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[4]

Seward Township
Township
Combined township building and fire station
Location in Winnebago County
Coordinates: 42°14′45″N 89°20′19″W
CountryUnited States
StateIllinois
CountyWinnebago
EstablishedNovember 6, 1849 (1849-11-06)
Government
 • SupervisorGarelt S. Stahl
Area
 • Total35.82 sq mi (92.8 km2)
 • Land35.81 sq mi (92.7 km2)
 • Water0 sq mi (0 km2)  0%
Elevation
853 ft (260 m)
Population
 (2010)
 • Estimate 
(2016)[1]
889
 • Density25.6/sq mi (9.9/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
FIPS code17-201-68783
[2][3]

Geography

According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[4]

Demographics
Historical population
CensusPop.%±
2016 (est.)889[1]
U.S. Decennial Census[5]

References
  1. "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. U.S. Geological Survey Geographic Names Information System: Township of Seward
  3. Illinois Regional Archives Depository System. "Name Index to Illinois Local Governments". Illinois State Archives. Illinois Secretary of State. Retrieved 19 September 2014.
  4. "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-28.
  5. "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.


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