1880 United States presidential election in Massachusetts
The 1880 United States presidential election in Massachusetts took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.
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Turnout | 71.2%[1] ![]() | |||||||||||||||||||||||||
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Elections in Massachusetts |
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Massachusetts voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 18.95%.
Results
1880 United States presidential election in Massachusetts[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 165,198 | 58.53% | 13 | 100.00% | ||
Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 111,720 | 39.58% | 0 | 0.00% | ||
Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 4,548 | 1.61% | 0 | 0.00% | ||
Prohibition | Neal Dow of Maine | Henry Adams Thompson of Ohio | 682 | 0.24% | 0 | 0.00% | ||
N/A | Others | Others | 117 | 0.04% | 0 | 0.00% | ||
Total | 282,265 | 100.00% | 13 | 100.00% |
References
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1880 Presidential General Election Results - Massachusetts".
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