1848 United States presidential election in Iowa

The 1848 United States presidential election in Iowa took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1848 United States presidential election in Iowa

November 7, 1848
 
Nominee Lewis Cass Zachary Taylor
Party Democratic Whig
Home state Michigan Louisiana
Running mate William O. Butler Millard Fillmore
Electoral vote 4 0
Popular vote 11,238 9,930
Percentage 50.46% 44.59%

President before election

James K. Polk
Democratic

Elected President

Zachary Taylor
Whig

Iowa voted for the Democratic candidate Lewis Cass in the state's first presidential election, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Iowa by a margin of 5.87%.

Results

1848 United States presidential election in Iowa[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Lewis Cass of Michigan William O. Butler of Kentucky 11,238 50.46% 4 100.00%
Whig Zachary Taylor of Louisiana Millard Fillmore of New York 9,930 44.59% 0 0.00%
Free Soil Martin Van Buren of New York Charles F. Adams, Sr. of Massachusetts 1,103 4.95% 0 0.00%
Total 22,271 100.00% 4 100.00%

References

  1. "1848 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 27 December 2013.
  2. "1848 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 27 December 2013.


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