1891 Iowa gubernatorial election
The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Herman C. Wheeler with 49.40% of the vote.
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| Elections in Iowa |
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State government |
General election
Candidates
Major party candidates
- Horace Boies, Democratic
- Herman C. Wheeler, Republican
Other candidates
- A. J. Westfall, People's
- Isaac T. Gibson, Prohibition
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | Horace Boies | 207,594 | 49.40% | ||
| Republican | Herman C. Wheeler | 199,381 | 47.45% | ||
| People's | A. J. Westfall | 12,303 | 2.93% | ||
| Prohibition | Isaac T. Gibson | 915 | 0.22% | ||
| Majority | 8,213 | ||||
| Turnout | |||||
| Democratic hold | Swing | ||||
References
- Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 9, 2020.
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