1944 Iowa gubernatorial election

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

1944 Iowa gubernatorial election

November 7, 1944
 
Nominee Robert D. Blue Richard F. Mitchell
Party Republican Democratic
Popular vote 561,827 437,684
Percentage 56.01% 43.63%

Governor before election

Bourke B. Hickenlooper
Republican

Elected Governor

Robert D. Blue
Republican

Primary elections

Primary elections were held on June 5, 1944.[1]

Candidates

Results

Democratic primary results[1]
Party Candidate Votes %
Democratic Richard F. Mitchell 38,086 100.00
Total votes 38,086 100.00

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican Robert D. Blue 102,246
Republican Henry W. Burma 63,011
Republican Milton W. Strickler 9,859
Total votes

General election

Candidates

Major party candidates

  • Robert D. Blue, Republican
  • Richard F. Mitchell, Democratic

Other candidates

  • Glen Williamson, Prohibition
  • Hugo Bockewitz, Socialist

Results

1944 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican Robert D. Blue 561,827 56.01%
Democratic Richard F. Mitchell 437,684 43.63%
Prohibition Glen Williamson 2,815 0.28%
Socialist Hugo Bockewitz 832 0.08%
Majority 124,143
Turnout
Republican hold Swing

References

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