1899 Iowa gubernatorial election

The 1899 Iowa gubernatorial election was held on November 7, 1899. Incumbent Republican L. M. Shaw defeated Democratic nominee Frederick Edward White with 55.26% of the vote.

1899 Iowa gubernatorial election

November 7, 1899
 
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 239,464 183,301
Percentage 55.26% 42.30%

Governor before election

L. M. Shaw
Republican

Elected Governor

L. M. Shaw
Republican

General election

Candidates

Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • Marshall W. Atwood, Prohibition
  • Charles Lloyd, People's
  • M. J. Kremer, Socialist Labor
  • C. C. Heacock, United Christian

Results

1899 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican L. M. Shaw 239,464 55.26%
Democratic Frederick Edward White 183,301 42.30%
Prohibition Marshall W. Atwood 7,639 1.76%
People's Charles Lloyd 1,698 0.39%
Socialist Labor M. J. Kremer 757 0.18%
Independent C. C. Heacock 484 0.11%
Majority 56,163
Turnout
Republican hold Swing

References

  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 7, 2020.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.