1889 Iowa gubernatorial election

The 1889 Iowa gubernatorial election was held on November 5, 1889. Democratic nominee Horace Boies defeated Republican nominee Joseph Hutchinson with 49.90% of the vote.

1889 Iowa gubernatorial election

November 5, 1889
 
Nominee Horace Boies Joseph Hutchinson
Party Democratic Republican
Popular vote 180,106 173,450
Percentage 49.90% 48.05%

Governor before election

William Larrabee
Republican

Elected Governor

Horace Boies
Democratic

General election

Candidates

Major party candidates

  • Horace Boies, Democratic
  • Joseph Hutchinson, Republican

Other candidates

  • S. B. Downing, Union Labor
  • Malcolm Smith, Prohibition

Results

1889 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Democratic Horace Boies 180,106 49.90%
Republican Joseph Hutchinson 173,450 48.05%
Labor S. B. Downing 5,773 1.60%
Prohibition Malcolm Smith 1,362 0.38%
Majority 6,656
Turnout
Democratic gain from Republican Swing

References

  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 12, 2020.
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