1872 United States presidential election in Iowa

The 1872 United States presidential election in Iowa took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose 11 electors to the Electoral College, which selected the president and vice president.

1872 United States presidential election in Iowa

November 5, 1872
 
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Ohio New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 11 0
Popular vote 131,566 71,189
Percentage 60.81% 32.90%

President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

Iowa was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri.

Grant won the state by a margin of 27.91%.

Results

1872 United States presidential election in Iowa[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 131,566 60.81% 11 100.00%
Liberal Republican Horace Greeley of New York Benjamin Gratz Brown of Missouri 71,189 32.90% 0 0.00%
Liberal Republican N/A of N/A N/A of N/A 10,447 4.83% 0 0.00%
Bourbon Democrat Charles O'Conor John Quincy Adams II 2,221 1.03% 0 0.00%
Write-ins N/A N/A 942 0.44% 0 0.00%
Total 216,365 100.00% 11 100.00%

References

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