1990 Wyoming gubernatorial election

The Wyoming gubernatorial election of 1990 took place on November 6, 1990. Incumbent Democrat Mike Sullivan ran for re-election as Governor of Wyoming. Sullivan defeated Republican businesswoman Mary Mead.

1990 Wyoming gubernatorial election

November 6, 1990 (1990-11-06)
Turnout71.99% Registered 2.00%
35.30% of Total Population 0.22%
 
Nominee Mike Sullivan Mary Mead
Party Democratic Republican
Popular vote 104,638 55,471
Percentage 65.4% 34.6%

County Results

Sullivan:      50–60%      60–70%      70–80%

Mead:      50-60%

Governor before election

Mike Sullivan
Democratic

Elected Governor

Mike Sullivan
Democratic

Democratic primary

Candidates

Democratic primary results[1]
Party Candidate Votes %
Democratic Mike Sullivan (inc.) 38,447 88.44
Democratic Ron Clingman 5,026 11.56
Total votes 43,473 100

Republican primary

Candidates

Republican primary results[2]
Party Candidate Votes %
Republican Mary Mead 51,560 67.25
Republican Nyla Murphy 24,916 32.75
Total votes 76,476 100

Results

Wyoming gubernatorial election, 1990[3]
Party Candidate Votes % ±%
Democratic Mike Sullivan (incumbent) 104,638 65.35 +11.39%
Republican Mary Mead 55,471 34.65 -11.39%
Total votes 160,109 100.00 N/A

References

  1. "WY Governor - D Primary". Our Campaigns. Retrieved December 11, 2017.
  2. "WY Governor - R Primary". Our Campaigns. Retrieved December 11, 2017.
  3. "1990 Gubernatorial General Election Results - Wyoming". U.S Election Atlas. Retrieved 30 April 2017.


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