1906 Wyoming gubernatorial election

The Wyoming gubernatorial election of 1906 took place on November 6, 1906. The Republican incumbent Bryant Butler Brooks defeated the Democratic Stephen A. D. Keister with 60.20% of the vote.

Wyoming gubernatorial election, 1906

November 6, 1906 (1906-11-06)
Turnout29.29% of Total Population 4.11
 
Nominee Bryant Butler Brooks Stephen A. D. Keister
Party Republican Democratic
Popular vote 16,317 9,444
Percentage 60.20% 34.85%

County Result

Governor before election

Bryant Butler Brooks
Republican

Elected Governor

Bryant Butler Brooks
Republican

Results

Wyoming gubernatorial election, 1906[1]
Party Candidate Votes %
Republican Bryant Butler Brooks 16,317 60.20%
Democratic Stephen A. D. Keister 9,444 34.85%
Socialist William L. O'Neill 1,236 4.56%
Independent George W. Blain 106 0.39%
Total votes 27,103 100%

Results by county

County Brooks Votes Keister Votes O'Neill Votes Blain Votes
Uinta 59.34% 2,259 28.24% 1,075 12.19% 465 0.24% 9
Big Horn 66.00% 1,807 32.18% 881 1.57% 43 0.26% 7
Fremont 35.51% 722 62.52% 1,271 1.43% 29 0.54% 11
Sweetwater 59.83% 1,010 32.46% 548 7.41% 125 0.30% 5
Sheridan 54.92% 1,411 37.02% 951 7.82% 201 0.23% 6
Johnson 56.54% 666 42.44% 500 0.93% 11 0.08% 1
Natrona 63.00% 664 37.00% 390 0.00% 0 0.00% 0
Carbon 65.82% 1,579 30.47% 548 3.50% 84 0.21% 5
Crook 64.40% 747 31.29% 363 4.05% 47 0.26% 3
Weston 70.18% 633 29.16% 263 0.55% 5 0.11% 1
Converse 68.57% 1,023 27.95% 417 1.27% 19 2.21% 33
Albany 57.45% 1,342 32.83% 767 8.73% 204 0.98% 23
Laramie 65.49% 2,454 34.45% 1,287 0.11% 4 0.05% 2

References

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