1870 Vermont gubernatorial election

The 1870 Vermont gubernatorial election took place on September 6, 1870. In keeping with the "Mountain Rule",[1] incumbent Republican George W. Hendee, who had succeeded to the governorship at the death of Peter T. Washburn, did not run for election to a full term as Governor of Vermont. Republican candidate John W. Stewart defeated Democratic candidate Homer W. Heaton to succeed Hendee. The 1870 election marked the start of biennial gubernatorial elections in Vermont.

1870 Vermont gubernatorial election

September 6, 1870 (1870-09-06)
 
Candidate John W. Stewart Homer W. Heaton
Party Republican Democratic
Popular vote 33,367 12,058
Percentage 73.4% 26.5%

Governor before election

George W. Hendee
Republican

Elected Governor

John W. Stewart
Republican

Results

Vermont gubernatorial election, 1870[2]
Party Candidate Votes % ±%
Republican John W. Stewart 33,367 73.4 -0.1
Democratic Homer W. Heaton 12,058 26.5 +0.1
N/A Other 4 0.0 -0.1
Total votes '45,429' '100'

References

  1. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 4 October 2015.
  2. "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 4 October 2015.
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