1940 United States Senate election in Vermont

The 1940 United States Senate election in Vermont took place on November 5, 1940. Incumbent Republican Warren Austin successfully ran for re-election to another term in the United States Senate, defeating Democratic candidate Ona S. Searles. Austin would resign in August 1946 to become United States Ambassador to the United Nations; Ralph Flanders was appointed to replace him and went on to win election to a full term in 1946.

1940 United States Senate election in Vermont

November 5, 1940 (1940-11-05)
 
Nominee Warren Austin Ona Searles
Party Republican Democratic
Popular vote 93,283 47,101
Percentage 66.4% 33.6%

U.S. senator before election

Warren Austin
Republican

Elected U.S. Senator

Warren Austin
Republican

Republican primary

Candidates

Results

1940 Republican Senate primary[1]
Party Candidate Votes %
Republican Warren Austin (incumbent) 60,603 99.89%
Write-in 65 0.11%
Total votes 60,668 100.00%

Democratic primary

Candidates

Results

1940 Democratic Senate primary[1]
Party Candidate Votes %
Democratic Ona S. Searles 5,340 99.39%
Write-in 33 0.61%
Total votes 5,373 100.00%

General election

Results

United States Senate election in Vermont, 1940[2]
Party Candidate Votes % ±%
Republican Warren Austin (inc.) 93,283 66.45% 15.41
Democratic Ona S. Searles 47,101 33.55% 15.41
Total votes 140,384 100.00%

See also

  • United States Senate elections, 1940 and 1941

References

  1. "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
  2. "General Election Results - U.S. Senator - 1914-2014" (PDF). Office of the Vermont Secretary of State. Retrieved 16 June 2015.
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