1876 United States presidential election in Vermont

The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

1876 United States presidential election in Vermont

November 7, 1876
 
Nominee Rutherford B. Hayes Samuel J. Tilden
Party Republican Democratic
Home state Ohio New York
Running mate William A. Wheeler Thomas A. Hendricks
Electoral vote 5 0
Popular vote 44,091 20,254
Percentage 68.30% 31.38%

County Results
Hayes
  50–60%
  60–70%
  70–80%
  80–90%


President before election

Ulysses S. Grant
Republican

Elected President

Rutherford B. Hayes
Republican

Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.

With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.[1]

Results

1876 United States presidential election in Vermont[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Rutherford B. Hayes of Ohio William A. Wheeler of New York 44,091 68.30% 5 100.00%
Democratic Samuel J. Tilden of New York Thomas A. Hendricks of Indiana 20,254 31.38% 0 0.00%
N/A Others Others 208 0.32% 0 0.00%
Total 64,553 100.00% 5 100.00%

See also

References

  1. "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. "1876 Presidential General Election Results - Vermont".
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